SAT考试数学练习题第六套 SAT problem solving practice test 6
1. Which of the following can be used to illustrate that not all prime numbers are odd?
A. 1
B. 2
C. 3
D. 4
E. 5
2. What is the greatest of 3 consecutive integers whose sum is 24 ?
A. 6
B. 7
C. 8
D. 9
E. 10
3. Considering the positions on the number line above, which of the following could be a value for x?
A. 5/3
B. 3/5
C. -2/5
D. -5/2
E. none
4. A piece of ribbon 4 yards long is used to make bows requiring 15 inches of ribbon for each. What is the maximum number of bows that can be made?
A. 8
B. 9
C. 10
D. 11
E. 12
5. How many numbers between 200 and 400 begin or end with 3 ?
A. 20
B. 60
C. 100
D. 110
E. 120
6. If f(3) = 15 and f(5) = 45, which of the following could be f(x)?
A. 4x + 3
B. 2x2 – 2x
C. 2x2 - x
D. 2x2 - 5
E. 5x2
7. PQRS is a parallelogram and ST = TR. What is the ratio of the area of triangle QST to the area of the parallelogram?
A. 1 : 2
B. 1 : 3
C. 1 : 4
D. 1 : 5
E. it cannot be determined
8. A picture is copied onto a sheet of paper 8.5 inches by 10 inches. A 1.5 inch margin is left all around. What area in square inches does the picture cover?
A. 76
B. 65
C. 59.5
D. 49
E. 38.5
9. The table shows the results of a poll which asked drivers how many accidents they had had over the previous 5 years. What is the median number of accidents per driver?
A. 0.5
B. 1
C. 1.5
D. 2
E. 4
10. If V = 12R / (r + R) , then R =
A. Vr / (12 - V)
B. Vr + V /12
C. Vr - 12
D. V / r - 12
E. V (r + 1) /12
SAT考试数学练习题第6套参考答案:
1.Correct Answer: B
Explanation:
The only even numbers in the list are 2 and 4, but 4 is not a prime. So 2 can be used to illustrate the statement that all primes are not odd.
2.Correct Answer: D
Explanation:
The sum of three consecutive integers can be written as n + (n + 1) + (n + 2) = 3n + 3
If the sum is 24, we need to solve the equation 3n + 3 = 24; 3n = 21; n = 7
The greatest of the three numbers is therefore 7 + 2 = 9
3.Correct Answer: C
Explanation:
Since the cube lies between the number and its square on the number line, we must be looking for a negative fraction (between 0 and -1 on the number line). Only -2/5 is a negative fraction. (Try for yourself the results of squaring and cubing negative numbers less than -1, numbers greater than 1, positive fractions, 1 and -1, so that you can deal with all similar questions).
4.Correct Answer: B
Explanation:
The maximum number of bows will be 4 yards (= 4 x 36 inches) divided by 15 inches.
This gives 9.6. But as a fraction of a bow is no use, we can only make 9 bows.
5.Correct Answer: D
Explanation:
The numbers will be 203, 213, 223, 233, 243, 253, 263, 273, 283, 293, then all the numbers from 300 to 399 inclusive.
6.Correct Answer: C
Explanation:
Plug the values 3 and 5 from the question into the answer choices to check whether you get 15 and 45 respectively.
Starting with A: 4x + 3 works with 3 ( 4 x 3 + 3 = 15) but not with 5 (4 x 5 + 3 = 23)
You can check the rest yourself….
7.Correct Answer: C
Explanation:
SQ divides the parallelogram in half. Also QT divides the half parallelogram into half again (because the bases of triangles STQ and TRQ are equal and their heights are equal).#p#分页标题#e#
Triangle QST is therefore one quarter of the parallelogram. And the ratio is 1 : 4
8.Correct Answer: E
Explanation:
Draw out the diagram and you will see that the width of the picture becomes 8.5 - 3 = 5.5
The length becomes 10 - 3 = 7. The area is now 5.5 x 7 = 38.5
9.Correct Answer: C
Explanation:
The median is the middle number when ranked (or the average of the middle tow numbers if there are an even number of items in the list). If we list out in order we will write 17 zeros, 13 ones, 21 twos etc. Since there are 60 drivers, the median will come between the value for the 30th and 31st drivers. We can already see that starting at the zero end, the 30thdriver will be in the ones section of the list, but the 31st driver will be in the twos section. Hence the median is 1.5.
10.Correct Answer: A
Explanation:
We have to rearrange the equation to make R the subject.
Start by cross multiplying by (r + R); V (r + R) = 12R
Multiply out the bracket Vr + VR = 12R
Subtract VR from both sides (to collect 'R' terms on the same side): Vr = 12R - VR
Next put 'R' outside a bracket: Vr = R(12-V)
Finally divide both sides by (12-V): the answer is that R is equal to Vr/(12-V)