SAT考试数学练习题SAT Math Practice 2
☆6. If f(x) = │(x2 – 50)│, what is the value of f(-5) ?
A. 75
B. 25
C. 0
D. -25
E. -75
☆7. ( √2 - √3 )2 =
A. 5 - 2√6
B. 5 - √6
C. 1 - 2√6
D. 1 - √2
E. 1
☆8. 230 + 230 + 230 + 230 =
A. 8120
B. 830
C. 232
D. 230
E. 226
☆9. Amy has to visit towns B and C in any order. The roads connecting these towns with her home are shown on the diagram. How many different routes can she take starting from A and returning to A, going through both B and C (but not more than once through each) and not travelling any road twice on the same trip?
A. 10
B. 8
C. 6
D. 4
E. 2
☆10. In the figure above AD = 4, AB = 3 and CD = 9. What is the area of triangle AEC ?
A. 18
B. 13.5
C. 9
D. 4.5
E. 3
SAT考试数学练习题SAT Math Practice 2参考答案
☆6.Correct Answer: B
Explanation:
If x = -5, then (x2 – 50) = 25 – 50 = -25
But the sign │x│ means the absolute value of x (the distance between the number and zero on the number line). Absolute values are always positive.
│-25 │ = 25
☆7.Correct Answer: A
Explanation:
Expand as for (a + b)2.
(√2 - √3)(√2 - √3) = 2 - 2(√2 + √3) + 3 = 5 - 2 √6
☆8.Correct Answer: C
Explanation:
All four terms are identical therefore we have 4 (230).
But 4 = 22, and so we can write 22. 230
Which is equivalent to 232
☆9.Correct Answer: B
Explanation:
Amy can travel clockwise or anticlockwise on the diagram.
Clockwise, she has no choice of route from A to B, a choice of one out of two routes from B to C, and a choice of one out of two routes from C back to A. This gives four possible routes.
Similarly, anticlockwise she has four different routes.
Total routes = 8
☆10.Correct Answer: D
Explanation:
If we take AE as the base of triangle AEC, then the height is CD.
The height of the triangle is therefore, 9 (given).
To find the base we need to see that triangles AEB and CDE are similar. The ratio AB: CD, is therefore equal to the ratio AE: ED. The given information shows that the ratio is 3:9, or 1:3. Now dividing AD (4) in this ratio gives us AE as 1.
The area of AEC = ? base x height
=1/2 x 9 = 4.5