虽然gre数学部分，数学相对简单，但是考生即便对数学解题都有思路，但能够一次作对，还是比较艰难。有时候主要栽在看不懂题上。接下来就一起来看看今天内容：gre数学满分难吗?
gre数学满分难吗
如果说你问你朋友他的
实际上，由于GRE数学的内容题干是相对简单的，所以，想要把考试变的更有挑战性，唯一的办法就是把题干的表达方法复杂化。所以出题者就会尽可能的吧简单的语言和概念翻译成复杂的表达方式。当想要说“n is odd”的时候，题目会说“the remainder when n is divided by 2 is 1.”
在这样的情况下，为了能更快地答题，你需要能够快速解码GRE复杂的语言的能力。下面有几个例子，大家来看看，能不能解码：
1、the remainder when x is divided by 10 is 3.
2、p = n3 – n, where n is an integer
3、integer y has an odd number of distinct factors
4、|b| = –b
5、the positive integer q does not have a factor r such that 1
6、n = 2k + 1, where k is a positive integer
7、a2b3c4 > 0
8、 x and y are integers, and yx < 0
9、what is the greatest integer n for which 2n is a factor of 96?
以下是这9道题目的正确解读：
The units digit of x is 3 (the remainder when divided by 10 is always the same as the units digit).
pis the product of 3 consecutive integers. Factor out n first: n(n2 – 1). Then, factor the difference of squares: n(n + 1)(n – 1). A number × one GREater × one smaller = the product of 3 consecutives.
y is a perfect square (like 9, whose factors are 1, 3, & 9). Any non-square integer will have an even number of distinct factors (e.g. 5: 1 & 5, or 18: 1, 2, 3, 6, 9, & 18).
b must be negative. If the absolute value of b is equal to -1 times b, then b cannot be positive or 0; it must be negative.
q must be prime. If q were a non-prime integer, it would have at least one factor between 1 and itself.
n is odd. 2k must be even (regardless of what k is), so adding 1 to an even will give us an odd.
b must be positive. The even exponents hide the sign of a and c, but a2 and c4 must be positive, so b3 – and therefore b – must be positive.
y must be negative, because only a negative base would yield a negative term. And x must be odd, because an even exponent would make the term positive.
How many factors of 2 are there in 96? If we break 96 down, we get a prime factorization of 2×2×2×2×2×3, so 25 will be a factor of 96, but 26 won’t.
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