由于出题者会尽可能的吧简单的语言和概念翻译成复杂的表达方式。在这样的情况下，为了能更快地答题，你需要能够快速解码GRE考试内容：GRE数学练习题附答案
the remainder when x is divided by 10 is 3.
p = n3 – n, where n is an integer
integer y has an odd number of distinct factors
|b| = –b
the positive integer q does not have a factor r such that 1
n = 2k + 1, where k is a positive integer
a2b3c4 > 0
x and y are integers, and yx < 0
what is the greatest integer n for which 2n is a factor of 96?
现在呢，大家都已经自己思考过这些问题了，我们就来看看大家想的思考的是不是正确的答案。以下是这9道题目的正确解读：
The units digit of x is 3 (the remainder when divided by 10 is always the same as the units digit).
pis the product of 3 consecutive integers. Factor out n first: n(n2 – 1). Then, factor the difference of squares: n(n + 1)(n – 1). A number × one GREater × one smaller = the product of 3 consecutives.
y is a perfect square (like 9, whose factors are 1, 3, & 9). Any non-square integer will have an even number of distinct factors (e.g. 5: 1 & 5, or 18: 1, 2, 3, 6, 9, & 18).
b must be negative. If the absolute value of b is equal to -1 times b, then b cannot be positive or 0; it must be negative.
q must be prime. If q were a non-prime integer, it would have at least one factor between 1 and itself.
n is odd. 2k must be even (regardless of what k is), so adding 1 to an even will give us an odd.
b must be positive. The even exponents hide the sign of a and c, but a2 and c4 must be positive, so b3 – and therefore b – must be positive.
y must be negative, because only a negative base would yield a negative term. And x must be odd, because an even exponent would make the term positive.
How many factors of 2 are there in 96? If we break 96 down, we get a prime factorization of 2×2×2×2×2×3, so 25 will be a factor of 96, but 26 won’t.
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